A step-up transformer produces a secondary voltage that is?

A step-up transformer is designed to increase the voltage from the primary side to the secondary side. It achieves this by utilizing the principle of electromagnetic induction, where the turns ratio (the number of windings in the primary coil compared to the number of windings in the secondary coil) dictates that the voltage will increase if there are more turns in the secondary coil compared to the primary coil.

When the transformer steps up the voltage, the power on both sides of the transformer must remain balanced, assuming we are ignoring losses (like heat). Power is the product of voltage and current; therefore, if the voltage increases in the secondary, the current must decrease in order to keep the overall power approximately constant. This relationship can be expressed in the transformer equations:

• Voltage ratio: ( \frac{V_s}{V_p} = \frac{N_s}{N_p} )

• Current ratio: ( \frac{I_s}{I_p} = \frac{N_p}{N_s} )

Where (V) is voltage, (I) is current, and (N) is the number of turns in the coils.

Consequently, in a step-up transformer, you can expect the secondary voltage to be higher than the